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x^2-236x+8684.8=0
a = 1; b = -236; c = +8684.8;
Δ = b2-4ac
Δ = -2362-4·1·8684.8
Δ = 20956.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-236)-\sqrt{20956.8}}{2*1}=\frac{236-\sqrt{20956.8}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-236)+\sqrt{20956.8}}{2*1}=\frac{236+\sqrt{20956.8}}{2} $
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